[Leetcode] Maximum Length of Pair Chain, Solution

You are given n pairs of numbers. In every pair, the first number is always smaller than the second number.

Now, we define a pair (c, d) can follow another pair (a, b) if and only if b < c. Chain of pairs can be formed in this fashion.

Given a set of pairs, find the length longest chain which can be formed. You needn't use up all the given pairs. You can select pairs in any order.

Example 1:

Input: [[1,2], [2,3], [3,4]]
Output: 2
Explanation: The longest chain is [1,2] -> [3,4]

Note:

1. The number of given pairs will be in the range [1, 1000].

[Thoughts]
按照数组的结束数字排序，然后从左到右扫描。如果满足b<c的条件，则count+1.


[Code]

1:    int findLongestChain(vector<vector<int>>& pairs) {  
2:      if(pairs.size() == 0) return 0;  
3:        
4:      std::sort(pairs.begin(), pairs.end(), comp);  
5:        
6:      int count = 1;  
7:      vector<int>& pair = pairs[0];  
8:      for(int i =1; i<pairs.size(); i++) {  
9:        if(pairs[i][0] > pair[1]) {  
10:          count ++;  
11:          pair = pairs[i];  
12:        }  
13:      }  
14:        
15:      return count;  
16:    }  
17:      
18:    static bool comp(vector<int>& a, vector<int>& b) {  
19:      return a[1] < b[1];  
20:    }