Given a collection of intervals, merge all overlapping intervals.
For example,
Given
return
» Solve this problemGiven
[1,3],[2,6],[8,10],[15,18]
,return
[1,6],[8,10],[15,18]
.[Thoughts]
复用一下Insert Intervals的解法即可,http://fisherlei.blogspot.com/2012/12/leetcode-insert-interval.html
创建一个新的interval集合,然后每次从旧的里面取一个interval出来,然后插入到新的集合中。
[Code]
黄色高亮部分是复用的Code.
1: vector<Interval> merge(vector<Interval> &intervals) {
2: vector<Interval> result;
3: for(int i =0; i< intervals.size(); i++)
4: {
5: insert(result, intervals[i]);
6: }
7: return result;
8: }
9: void insert(vector<Interval> &intervals, Interval newInterval) {
10: vector<Interval>::iterator it = intervals.begin();
11: while(it!= intervals.end())
12: {
13: if(newInterval.end<it->start)
14: {
15: intervals.insert(it, newInterval);
16: return;
17: }
18: else if(newInterval.start > it->end)
19: {
20: it++;
21: continue;
22: }
23: else
24: {
25: newInterval.start = min(newInterval.start, it->start);
26: newInterval.end = max(newInterval.end, it->end);
27: it =intervals.erase(it);
28: }
29: }
30: intervals.insert(intervals.end(), newInterval);
31: }
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