Thursday, July 27, 2017

[Leetcode] Maximum Length of Pair Chain, Solution

You are given `n` pairs of numbers. In every pair, the first number is always smaller than the second number.
Now, we define a pair `(c, d)` can follow another pair `(a, b)` if and only if `b < c`. Chain of pairs can be formed in this fashion.
Given a set of pairs, find the length longest chain which can be formed. You needn't use up all the given pairs. You can select pairs in any order.
Example 1:
```Input: [[1,2], [2,3], [3,4]]
Output: 2
Explanation: The longest chain is [1,2] -> [3,4]
```
Note:
1. The number of given pairs will be in the range [1, 1000].

[Thoughts]

[Code]

``````1:    int findLongestChain(vector<vector<int>>& pairs) {
2:      if(pairs.size() == 0) return 0;
3:
4:      std::sort(pairs.begin(), pairs.end(), comp);
5:
6:      int count = 1;
7:      vector<int>& pair = pairs;
8:      for(int i =1; i<pairs.size(); i++) {
9:        if(pairs[i] > pair) {
10:          count ++;
11:          pair = pairs[i];
12:        }
13:      }
14:
15:      return count;
16:    }
17:
18:    static bool comp(vector<int>& a, vector<int>& b) {
19:      return a < b;
20:    }
``````